Borrar filtros
Borrar filtros

Data type symfun (code problem)

3 visualizaciones (últimos 30 días)
Patryk
Patryk el 22 de Mayo de 2024
Movida: Torsten el 22 de Mayo de 2024
the content of the task:
Follow these steps to obtain expressions for the critical values ​​of f(x)=x^(3/5)*(4-x)^(1/3):
  1. Define the symbolic function f(x) corresponding to the above formula.
  2. Use the diff function to differentiate f(x) and define the symbolic function df(x).
  3. Use the numden function to obtain symbolic expressions for the numerator and denominator of df(x) and store them in the variables n and d, respectively.
  4. Use the solve function to solve the equations n(x)=0 and d(x)=0. Assign them to the nzeros and zeroros variables respectively.
I have a problem, for this task:
Use the solve function to solve the equations n(x) = 0 and d(x)=0.
Here is my code:
syms x
f(x) = x^(3/5) * (4 - x)^(1/3);
df(x) = diff(f(x));
[n d] = numden(df(x));
nzeros = solve(n == 0);
dzeros = solve(d == 0);
%%%%%%% Kod rysujący jest poniżej %%%%%%%%
figure; hold on; grid on;
fplot(f(x),'LineWidth',2);
fplot(df(x),'LineWidth',2);
ylim([-6,6]);
legend('$f(x)$','$f''(x)$','Interpreter','latex','FontSize',14);
Assign them to the "nzeros" and "dzeros" I can't write lines 5 and lines 6 of the code correctly
Code error:
Variable n must be of data type symfun. It is currently of type sym. Check where the variable is assigned a value.
I tried replacing the code like this:
syms x
f(x) = x^(3/5) * (4 - x)^(1/3);
df(x) = diff(f(x));
[n d] = numden(df(x));
nzeros = solve(symfun(n,x) == 0);
dzeros = solve(symfun(d,x) == 0);
%%%%%%% Kod rysujący jest poniżej %%%%%%%%
figure; hold on; grid on;
fplot(f(x),'LineWidth',2);
fplot(df(x),'LineWidth',2);
ylim([-6,6]);
legend('$f(x)$','$f''(x)$','Interpreter','latex','FontSize',14);
However, the same error message keeps popping up.
Can anyone help?

Respuestas (2)

Torsten
Torsten el 22 de Mayo de 2024
If your MATLAB release throws an error (R2024a does not as you can see above), try
[n(x) d(x)] = numden(df(x))
instead of
[n d] = numden(df(x))
  1 comentario
Patryk
Patryk el 22 de Mayo de 2024
Movida: Torsten el 22 de Mayo de 2024
replacing [n d] = numden(df(x)) with [n(x) d(x)] = numden(df(x)) helped! Thank you very much :)

Iniciar sesión para comentar.


Paul
Paul el 22 de Mayo de 2024
Hi Patryk,
Works o.k. here. What version of Matlab are you using?
syms x
f(x) = x^(3/5) * (4 - x)^(1/3);
df(x) = diff(f(x));
[n d] = numden(df(x))
n = 
d = 
nzeros = solve(n == 0)
nzeros = 
dzeros = solve(d == 0)
dzeros = 
  1 comentario
Patryk
Patryk el 22 de Mayo de 2024
Movida: Torsten el 22 de Mayo de 2024
I use Matlab online

Iniciar sesión para comentar.

Etiquetas

Productos


Versión

R2023b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by