Can handle class be used to simulate "Pointer" in C language?
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If I define a "Ptr" class as following:
classdef Ptr < handle
properties
data
end
end
then, objects of Ptr will behave like pointers in C language.
Is this true, guys?
1 comentario
Shunchao Wu
el 15 de Nov. de 2011
Respuestas (2)
Daniel Shub
el 15 de Nov. de 2011
1 voto
Objects of the handle class are not identical to pointers. When you pass an object to a function (whether it is a value class or a handle class), MATLAB does not immediately make a copy of the object. It is almost like it passes a pointer (but it is not a pointer). MATLAB has a complicated COW and tries not to copy the object unless it needs to. With a high level language of MATLAB you have to give up some of the control on memory management and hope MATLAB behaves in a reasonable manner.
3 comentarios
Shunchao Wu
el 15 de Nov. de 2011
per isakson
el 15 de Nov. de 2011
Undocumented Matlab at, http://undocumentedmatlab.com/ , might interest you.
Shunchao Wu
el 16 de Nov. de 2011
Titus Edelhofer
el 15 de Nov. de 2011
Hi,
"then objects of Ptr will behave like pointers". If the behaviour you mean is that once you change a Ptr, all other variables that "point" to the same object are changed as well, then yes. Example:
x = Ptr;
y = x; % both x and y "point" to the same object
x.data = 2; % now y.data is 2 as well
But I would say that "reference" like the & in C++ comes nearer to what handle classes are ...
Titus
5 comentarios
Shunchao Wu
el 15 de Nov. de 2011
Friedrich
el 15 de Nov. de 2011
Titus is right here. Its a reference:
The handle class is the superclass for all classes that follow handle semantics. A handle is a reference to an object. If you copy an object's handle, MATLAB copies only the handle and both the original and copy refer to the same object data. If a function modifies a handle object passed as an input argument, the modification affects the original input object.
Shunchao Wu
el 15 de Nov. de 2011
Titus Edelhofer
el 16 de Nov. de 2011
hmm, why not? When you pass an object by reference to a function, the function may change the underlying/referenced object. Of course only, as long as you don't pass a const reference ... Or do I remember entirely wrong, since my C++ programming is about 10 years ago by now ;-).
Shunchao Wu
el 19 de Nov. de 2011
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