increasing precison using fprintf for text file
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sermet
el 23 de Abr. de 2015
Editada: per isakson
el 23 de Abr. de 2015
cellArray =
[ 334] [38.141794059793398] [31.983184186130529] [1.751451095529832e+03]
[ 352] [38.094455446389709] [31.940682658186898] [1.779530219110660e+03]
[ 404] [38.162956465159276] [32.019563510560964] [1.542875077314675e+03]
[ 414] [38.176654734516106] [32.068817577008474] [1.389497182917781e+03]
[ 476] [38.075635175382899] [32.027977260576755] [1.994276513063349e+03]
[2729] [38.229399882994215] [31.934421897750756] [1.167495300253853e+03]
[2730] [38.205404821919039] [31.911611428797361] [1.291408437962644e+03]
[2742] [38.104502101643973] [31.931891003528762] [1.774978352412581e+03]
Name Size Bytes Class Attributes
cellArray 8x4 3840 cell global
% I use below codes to write cellArray into txt file
startingFolder='C:\Program Files\MATLAB';
if ~exist(startingFolder, 'dir');
startingFolder = pwd;
end
defaultFileName=fullfile(startingFolder, '*.txt');
[baseFileName, folder]=uiputfile(defaultFileName, 'Select a file');
if baseFileName == 0
return
end
fullFileName = fullfile(folder, baseFileName);
c=cellfun(@num2str,cellArray,'un',0);
[n,m]=size(c);
form=[repmat('%s ',1,m) ' \r\n'];
fid = fopen(fullFileName, 'w');
for k=1:n
fprintf(fid, form, c{k,:});
end
fclose(fid);
% but data (2-3-4rd columns) are written only 4 numbers after the comma (like, 38.1418). I need to write the data into txt file without rounding.
3 comentarios
per isakson
el 23 de Abr. de 2015
Editada: per isakson
el 23 de Abr. de 2015
Replace
@num2str
by
@(str) num2str( str, format_specifier )
or better
>> cellfun( @num2str, {123,34567/3}, {'%d','%18.12f'}, 'uni', false )
ans =
'123' '11522.333333333334'
Respuesta aceptada
Star Strider
el 23 de Abr. de 2015
If you need full precision on all numeric variables and want to use repmat to create your ‘form’ format descriptors, instead of %s, I would use %23.15E. That will print all of them out to full precision.
7 comentarios
Star Strider
el 23 de Abr. de 2015
No worries.
The only change I suggested is to use this assignment for ‘form’:
form = '%5d %23.15E %23.15E %23.15E\n';
Experiment with it to see if it works to your satisfaction.
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