Not enough input arguments.

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Anonymous Chupacabra
Anonymous Chupacabra el 26 de Abr. de 2015
Comentada: Anonymous Chupacabra el 27 de Abr. de 2015
I have a file called F.m which contains the following code:
1 % INPUT:
2 % 3D vector x
3 %
4 % OUTPUT:
5 % function value at x
6
7 function val = f(x)
8 val= x(1)^2 + x(1)*x(2)^3 - 12*x(3) + 4;
9 end
I am trying to call F.m in an algorithm in another file, but when I run the code, I get the following error:
"Error using F (line 8) Not enough input arguments."
I'm new to MATLAB, so I'm not sure what I'm doing wrong here. Any help would be greatly appreciated!
  2 comentarios
Aaron Powers
Aaron Powers el 26 de Abr. de 2015
Could you include the code that calls your function f, with an example of what x is?
Anonymous Chupacabra
Anonymous Chupacabra el 26 de Abr. de 2015
Thank you for your interest in my question, Aaron!
x is a 3D point/vector, for example x = (x(1), x(2), x(3)) = (0,1,2).
Here's the code (it also calls on 2 other algorithms and requires input of other values too):
function [xminest, fminest,k] = Algorithm1(f, gradf, x0, tol1, tol2, T)
k = 0;
xk = x0;
while ( norm(feval(gradf, xk)) >= tol1 )
%du = feval(gradf, xk);
%dk = -du/norm(du);
dk = -1*feval(gradf, xk);
[a, b] = Algorithm2(f, xk, dk, T);
[tmin, fmin] = Algorithm3(f, a, b, tol2, xk, dk);
k = k + 1;
xk = xk + tmin*dk;
end
fminest = feval(f,xminest);
To run the code, I enter the command:
Algorithm1(F, gradf, [0,1,2], 0.1, 0.1, 10)

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the cyclist
the cyclist el 26 de Abr. de 2015
With the syntax
Algorithm1(F, gradf, [0,1,2], 0.1, 0.1, 10)
MATLAB is looking for a variable named F (and similarly with gradf). You need to tell it that F is a function, by passing the function handle:
Algorithm1(@F, @gradf, [0,1,2], 0.1, 0.1, 10)
It looks like you have similar problems deeper in your code, but I could not resolve them completely because I don't have all the functions you are using.
  1 comentario
Anonymous Chupacabra
Anonymous Chupacabra el 27 de Abr. de 2015
Thank you very much, cyclist! After prefacing each file name with @ as you said, the code is executing as intended!

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Más respuestas (1)

Jan
Jan el 26 de Abr. de 2015
Editada: Jan el 26 de Abr. de 2015
Inside this line:
[a, b] = Algorithm2(f, xk, dk, T);
you call the function "f" without arguments. But You want top provide the function handle of this file instead:
[a, b] = Algorithm2(@f, xk, dk, T);
Note: In modern Matlab versions you can omit the feval and call the function handle directly, which looks nicer:
while norm(gradf(xk)) >= tol1
  1 comentario
Anonymous Chupacabra
Anonymous Chupacabra el 27 de Abr. de 2015
Thank you very much, Jan! Using the function handle as you showed worked! Thank you also for your tip, as I have the 2015 MATLAB version, but I think the algorithm code I am using may be quite old.

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