Borrar filtros
Borrar filtros

How can I solve the error "Unable to solve the collocation equations -- a singular Jacobian encountered" in bvp4c?

6 visualizaciones (últimos 30 días)
I tried to solve the bvp using bvp4c procedure. But I have an error "Unable to solve the collocation equations -- a singular Jacobian encountered." How to resolve this issue?
proj()
Error using bvp4c (line 196)
Unable to solve the collocation equations -- a singular Jacobian encountered.

Error in solution>proj (line 31)
sol= bvp4c(@projfun,@projbc,solinit,options);
function sol= proj
A = 0.5;
Gr = 0.7;
Gc = 0.5;
Kp = 3.0;
beta = 0.5;
Pr = 0.3;
Df = 0.2;
Sc = 0.1;
L0 = 0.5;
Sr = 0.3;
M = 1;
Bi1 = 0.5;
Bi2 = 0.5;
K0 = 0.3;
myLegend1 = {};myLegend2 = {};
rr = [0.3 0.5 0.8];
for i =1:numel(rr)
Re = rr(i);
y0 = [1, 0, 1, 1, 0, 1, 0];
options =bvpset('stats','on','RelTol',1e-4);
x = linspace(0,10,500);
solinit = bvpinit(x,y0);
sol= bvp4c(@projfun,@projbc,solinit,options);
disp((sol.y(1,20)))
figure(1)
plot(sol.x,(sol.y(6,:)))
grid on,hold on
myLegend1{i}=['Pr = ',num2str(rr(i))];
xlabel('eta');
ylabel('(thetas-thetaf)/thetas');
i=i+1;
end
figure(1)
legend(myLegend1)
hold on
function dy= projfun(~,y)
dy= zeros(7,1);
dy(1) = y(2);
dy(2) = y(3);
dy(3) = (0.5*A*y(3) - Gr*y(4) - Gc*y(6) + (M + Kp + A)*y(2)) / (1 + (1/beta));
dy(4) = y(5);
dy(5) = (Pr*(0.5*A*y(5)) - Pr*Df*Sc*(0.5*A*y(7) + 2*A*y(6) - L0*y(6))) / (1 - (Pr*Df*Sc*Sr));
dy(6) = y(7);
dy(7) = (Sc*(0.5*A*y(7) + 2*A*dy(6)) - Sr*Pr*(0.5*A*y(5) + 2*A*y(4))) / (1 - (Sr*Df*Pr));
end
function res= projbc(ya,yb)
res= [
ya(2) - (1 + K0*ya(3));
ya(5) + Bi1*(1 - ya(4));
ya(7) + Bi2*(1 - ya(6));
yb(2);
yb(4);
yb(6);
yb(7)];
end
end
  1 comentario
Torsten
Torsten el 29 de Jul. de 2024
How to resolve this issue?
It's not a technical issue. Usually, there is something wrong with the equations or the boundary conditions. So you should compare both of them with the mathematical description of the problem.

Iniciar sesión para comentar.

Respuesta aceptada

Torsten
Torsten el 29 de Jul. de 2024
Editada: Torsten el 29 de Jul. de 2024
Your ODE system is linear - thus you can determine its general solution having 7 free parameters. But incorporating of your boundary conditions leads to a linear system of equations where the coefficient matrix A is rank-deficient (rank 6 instead of rank 7). Consequently, your system is not solvable.
A = 0.5;
Gr = 0.7;
Gc = 0.5;
Kp = 3.0;
beta = 0.5;
Pr = 0.3;
Df = 0.2;
Sc = 0.1;
L0 = 0.5;
Sr = 0.3;
M = 1;
Bi1 = 0.5;
Bi2 = 0.5;
K0 = 0.3;
Mat = zeros(7);
Mat(1,2) = 1;
Mat(2,3) = 1;
Mat(3,2) = (M + Kp + A) / (1 + 1/beta);
Mat(3,3) = 0.5*A/(1 + 1/beta);
Mat(3,4) = -Gr/(1 + 1/beta);
Mat(3,6) = -Gc/(1 + 1/beta);
Mat(4,5) = 1;
Mat(5,5) = Pr*0.5*A/(1 - Pr*Df*Sc*Sr);
Mat(5,6) = - Pr*Df*Sc*(2*A - L0) / (1 - Pr*Df*Sc*Sr);
Mat(5,7) = - Pr*Df*Sc*0.5*A/ (1 - Pr*Df*Sc*Sr);
Mat(6,7) = 1;
Mat(7,4) = - Sr*Pr*2*A / (1 - Sr*Df*Pr);
Mat(7,5) = - Sr*Pr*0.5*A / (1 - Sr*Df*Pr);
Mat(7,7) = Sc*(0.5*A+2*A) / (1 - Sr*Df*Pr);
syms x1(t) x2(t) x3(t) x4(t) x5(t) x6(t) x7(t)
eqns = [diff(x1);diff(x2);diff(x3);diff(x4);diff(x5);diff(x6);diff(x7)]-Mat*[x1;x2;x3;x4;x5;x6;x7]==[0;0;0;0;0;0;0];
sol = dsolve(eqns,'MaxDegree',4)
sol = struct with fields:
x2: C3*(exp((t*(2976375*((13875*3^(1/2)*342589119285075140699353^(1/2))/1883723499362492536448 - 2321348855894375/1076413428207138592256)^(1/6) - 9802324*((3364850596725*((... x1: C1 + C2*(exp((t*(2976375*((13875*3^(1/2)*342589119285075140699353^(1/2))/1883723499362492536448 - 2321348855894375/1076413428207138592256)^(1/6) - 9802324*((33648505967... x3: C6*exp(-(t*(865^(1/2) - 1))/24) + C7*exp((t*(865^(1/2) + 1))/24) - C2*(exp((t*(2976375*((13875*3^(1/2)*342589119285075140699353^(1/2))/1883723499362492536448 - 23213488... x4: C2*(exp((t*(2976375*((13875*3^(1/2)*342589119285075140699353^(1/2))/1883723499362492536448 - 2321348855894375/1076413428207138592256)^(1/6) - 9802324*((3364850596725*((... x5: C4*exp((t*(9802324*((3364850596725*((13875*3^(1/2)*342589119285075140699353^(1/2))/1883723499362492536448 - 2321348855894375/1076413428207138592256)^(1/3))/960855558009... x6: C3*(exp((t*(2976375*((13875*3^(1/2)*342589119285075140699353^(1/2))/1883723499362492536448 - 2321348855894375/1076413428207138592256)^(1/6) - 9802324*((3364850596725*((... x7: C4*exp((t*(9802324*((3364850596725*((13875*3^(1/2)*342589119285075140699353^(1/2))/1883723499362492536448 - 2321348855894375/1076413428207138592256)^(1/3))/960855558009...
eqn1 = subs(sol.x2,t,0)-(1+K0*subs(sol.x3,t,0))==0;
eqn2 = subs(sol.x5,t,0)+Bi1*(1-subs(sol.x4,t,0))==0;
eqn3 = subs(sol.x7,t,0)+Bi2*(1-subs(sol.x6,t,0))==0;
eqn4 = subs(sol.x2,t,10)==0;
eqn5 = subs(sol.x4,t,10)==0;
eqn6 = subs(sol.x6,t,10)==0;
eqn7 = subs(sol.x7,t,10)==0;
[A,b] = equationsToMatrix([eqn1,eqn2,eqn3,eqn4,eqn5,eqn6,eqn7])
A = 
b = 
rank(A)
ans = 6
rank([A,b])
ans = 7

Más respuestas (0)

Categorías

Más información sobre Numerical Integration and Differential Equations en Help Center y File Exchange.

Etiquetas

Productos


Versión

R2015a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by