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Issues with looping in structure: variable in the name

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Joe
Joe el 22 de Ag. de 2024
Comentada: Voss el 23 de Ag. de 2024
I am loading one Excel spreadsheet with 11 tabs. The 11 tabs are named fl1, fl2,... fl11.
The spreadsheet is currently loaded into a structure named flight_data. I don't like the way it is organized, so I want to create a 11 new structures: somename1, somename2,....somename11.
I think the code will show how I'm trying to structure my data. The goal is to have 11 strutures that look like this:
%my loop that doesn't work
for i = 1:11
fpro(i).loc7.x = flight_data.fpro{i}(:,1)
end
%my structure setup
fpro(i).name = 'Flight Profile {i}';
fpro(i).loc7.x = flight_data.fl{i}(:,1)
fpro(i).loc9.x = flight_data.fl{i}(:,4)
fpro(i).loc10.x = flight_data.fl{i}(:,7)
fpro(i).loc7.y = flight_data.fl{i}(:,2)
fpro(i).loc9.y = flight_data.fl{i}(:,5)
fpro(i).loc10.y = flight_data.fl{i}(:,8)
fpro(i).loc7.z = flight_data.fl{i}(:,3)
fpro(i).loc9.z = flight_data.fl{i}(:,6)
fpro(i).loc10.z = flight_data.fl{i}(:,9)
  2 comentarios
Stephen23
Stephen23 el 22 de Ag. de 2024
Editada: Stephen23 el 22 de Ag. de 2024
"...I want to create a 11 new structures: somename1, somename2,....somename11."
Best avoided:
Rather than inefficiently forcing pseudo-indices into variable names just use actual indices into e.g. a structure array. Real indexing will be simpler and much more efficient thatn what you are attempting. Your approach will make working with your data more complex and inefficient.
Joe
Joe el 23 de Ag. de 2024
You are 100% correct...no excuses!

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Respuesta aceptada

Voss
Voss el 22 de Ag. de 2024
I guess this is something like your flight_data variable:
flight_data = struct('fl',{permute(num2cell(rand(10,9,11),[1 2]),[3 1 2])})
flight_data = struct with fields:
fl: {11x1 cell}
flight_data.fl
ans = 11x1 cell array
{10x9 double} {10x9 double} {10x9 double} {10x9 double} {10x9 double} {10x9 double} {10x9 double} {10x9 double} {10x9 double} {10x9 double} {10x9 double}
I think you're going for this:
clear('fpro')
for i = 1:numel(flight_data.fl)
fpro(i).name = sprintf('Flight Profile %d',i);
fpro(i).loc7.x = flight_data.fl{i}(:,1);
fpro(i).loc9.x = flight_data.fl{i}(:,4);
fpro(i).loc10.x = flight_data.fl{i}(:,7);
fpro(i).loc7.y = flight_data.fl{i}(:,2);
fpro(i).loc9.y = flight_data.fl{i}(:,5);
fpro(i).loc10.y = flight_data.fl{i}(:,8);
fpro(i).loc7.z = flight_data.fl{i}(:,3);
fpro(i).loc9.z = flight_data.fl{i}(:,6);
fpro(i).loc10.z = flight_data.fl{i}(:,9);
end
Check some of the results:
fpro
fpro = 1x11 struct array with fields:
name loc7 loc9 loc10
fpro(1)
ans = struct with fields:
name: 'Flight Profile 1' loc7: [1x1 struct] loc9: [1x1 struct] loc10: [1x1 struct]
fpro(2)
ans = struct with fields:
name: 'Flight Profile 2' loc7: [1x1 struct] loc9: [1x1 struct] loc10: [1x1 struct]
  2 comentarios
Joe
Joe el 23 de Ag. de 2024
I had to make a simple adjustment, but it worked. Thanks.
Voss
Voss el 23 de Ag. de 2024
You're welcome!

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