How to set zones for long transmission line that are valid for all faults
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A Lumbini
el 8 de Nov. de 2024
Comentada: A Lumbini
el 17 de Dic. de 2024
I am trying to implement three zonal protection in matlab and i have set zones that works good for LG fault but when i create LL fault in zone 1 the relay is responding as if fault is in zone 2.
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/1805223/image.png)
This is the matlab simulink model
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/1805228/image.png)
and this is single line diagram of it.[The pi section blocks are transmission lines]. Relay R1 will generate trip signal instantly when fault is in 80% of line 1 impedance[Zone1] and when fault occurs in remaining line it generates trip signal with some delay[Zone2]. I have set zones by creating LG fault at end of the zone means for Relay R1 zone 1 i have created fault at 160km of line 1.[because calculating 80% of impedance was difficult as the pi section blocks are having positive, negative and zero sequence impedance]
Digital Relay block in model consist of an algorithm which estimates Voltage and Current values and from this value impedances[Z] is calculated
ZR [R phase impedance], ZY [Y phase impedance], ZB [B phase impedance].
Yes, Red dots are impedance values calculated at different times[ The algorithm i used to estimate values uses samples so, whenever new current and voltage sample is produced impedance is calculated]
So i have created LL fault(between R and Y) at 160km of line 1 becauses set zones should work for all faults. But R phase impedances is entering into zone1 whereas Y phase is in zone 2
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/1804988/image.jpeg)
3 comentarios
William Rose
el 9 de Nov. de 2024
@A Lumbini, I'm not a simulink person so will not be able to assist you.
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MULI
el 11 de Dic. de 2024
Editada: MULI
el 11 de Dic. de 2024
I understand that the digital relay is misclassifying zones during a Line-to-Line (LL) fault because it evaluates individual phase impedances.
You can follow the below steps to resolve this issue:
- For LL faults (e.g., R-Y), calculate the loop impedance instead of individual phase impedances:
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/1820626/image.png)
- The loop impedance directly represents the fault's location and avoids inconsistencies caused by mutual coupling or independent phase evaluation.
- Modify your digital relay algorithm to compute
,
and
for LL faults.
- Compare these loop impedances with the set zone boundaries.
You can refer to the following link which provides the distance protection relay model and offers further insights in modelling: https://www.mathworks.com/matlabcentral/fileexchange/112610-distance-protection-relay
4 comentarios
MULI
el 17 de Dic. de 2024
You may find some helpful insights regarding distance protection in IEEE research papers. These resources provide a detailed explanation of fault behavior and its impact on impedance zones.
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