How to extract date time from format unique to InputFormat?
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I have data set extracted in the form ´05/17/24 04p:48:15.8148625´. These data sets are not fond in the InputFormat list, contains a 'p' for postmeridian, and has seconds up to 7 decimal places. I am ok if it is inevitable to round-off the seconds, however, I will be working with several formats and the manual way of extracting parts of strings, joining them together in InputFormat list is quite hectic and it slows down my code. Is there a way we can simply use datetime command to convert the text into datetime? I will appreciate your help. Thanks.
load('data_imp.mat');
dttime = datetime(data_imp,"InputFormat","MM/dd/uu 'T'HH:mm:ss.SSSSSSS");
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Más respuestas (2)
The format used to represent am/pm (04p:48:15.8148625) is not one recognized by MATLAB. You therefore need to manipulate your data into a format that MATLAB can recognize.
My approach would be
- capture which rows contain pm times
- remove the am/pm designation
- convert times to datetimes
- add 12 hours to rows containing pm times
load('data_imp.mat')
data_imp
% capture pm times
pmTms = cellfun(@(x) contains(x,'p:'),data_imp);
% remove am/pm designation
data_imp = replace(data_imp,lettersPattern + ':',':')
% convert to datetime
dttime = datetime(data_imp,"InputFormat","MM/dd/yy hh:mm:ss.SSSSSSS");
% add 12 hours to pm times
dttime(pmTms) = dttime + hours(12)
1 comentario
Muha
el 13 de Nov. de 2024
Another possibility:
str = "05/17/24 04p:48:15.8148625"
str = replace(str,"p","pm")
datetime(str,InputFormat="MM/dd/yy hha:mm:ss.SSSSSSS")
1 comentario
Cris LaPierre
el 21 de Nov. de 2024
That's pretty slick. Didn't think to try that.
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