asking about how to arrange 1000 EV with 8760 hours

Respuestas (1)

num_EV = 1000;
total_duration = 8760;
longest_ev_duration = 71; %adjust as appropriate
start_times = randi(total_duration, num_EV, 1);
ev_durations = randi(longest_ev_duration, num_EV, 1);
start_times = min(start_times, longest_ev_duration - ev_durations);
end_times = start_times + ev_durations;
Now each EV is due to start at start_times(K) and end at end_times(K)

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el 24 de Sept. de 2025

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el 24 de Sept. de 2025

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