How to use signal name as variable name in generated code
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Andrea Carignano
el 17 de Dic. de 2025 a las 22:37
Editada: Walter Roberson
el 20 de Dic. de 2025 a las 8:49
I have a simple model with an atomic subsystem block.
the signal after the subsystem "Function" is called "x" in the model.
The generated code for the step function is
void untitled1_step(void)
{
real32_T rtb_Gain;
/* Outputs for Atomic SubSystem: '<Root>/Function' */
/* Inport: '<Root>/In1' */
rtb_Gain = untitled1_Function(untitled1_U.In1);
/* End of Outputs for SubSystem: '<Root>/Function' */
/* Outport: '<Root>/Out2' incorporates:
* Bias: '<Root>/Bias'
*/
untitled1_Y.Out2 = rtb_Gain + 2.0F;
}
Embedded coder generate rtb_Gain variable.
However I would like to generate the x variable instead, so that the code became:
void untitled1_step(void)
{
real32_T rtb_Gain;
/* Outputs for Atomic SubSystem: '<Root>/Function' */
/* Inport: '<Root>/In1' */
x = untitled1_Function(untitled1_U.In1);
/* End of Outputs for SubSystem: '<Root>/Function' */
/* Outport: '<Root>/Out2' incorporates:
* Bias: '<Root>/Bias'
*/
untitled1_Y.Out2 = x + 2.0F;
}
Is there any general setting that I can activate to do this?
2 comentarios
Walter Roberson
el 20 de Dic. de 2025 a las 4:38
If you assign to x, why are you later using rtb_Gain + 2.0F instead of x + 2.0F ?
Respuestas (1)
Fangjun Jiang
el 19 de Dic. de 2025 a las 19:34
Double click the signal line and set the signal name as 'x'. That might be sufficient for your need.
Currently, the 'x' shown in your model looks like an annotation, not the signal name.
For more control, select the signal line, right click, select "Property" and set the signal line property.
One of the ways is to check "Name must resolve to signal object" and create a Simulink.Signal object in base workspace. Check the document for Simulink.Signal to learn more.
x=Simulink.Signal
1 comentario
Andrea Carignano
el 19 de Dic. de 2025 a las 21:47
Editada: Andrea Carignano
el 19 de Dic. de 2025 a las 21:48
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