3D Gaussian Decay from 1 to 0
1 visualización (últimos 30 días)
Mostrar comentarios más antiguos
Inês Rodrigues
el 26 de Mayo de 2015
Comentada: Inês Rodrigues
el 26 de Mayo de 2015
I'm doing a model in matlab and I want that, when my variable k is 1, it decays to 0 by a gaussian pattern. It's a 3D model, so the maximum 1 would decay in every direction. The result would be a matrix with the ones k gave me and the other elements between 0 and 1. Could you please help me?
0 comentarios
Respuesta aceptada
Image Analyst
el 26 de Mayo de 2015
Editada: Image Analyst
el 26 de Mayo de 2015
If you have the Image Processing Toolbox, you can use fspecial(). Of course since it's Gaussian, it will decay towards zero, not to zero. Gaussians can never equal zero.
If you don't have that toolbox, just use meshgrid() and exp() to create the Gaussian pattern. In fact, this might be easier for the 3D case since with fspecial, it just creates a 2D Gaussian so you'd have to call it repeatedly to get the third dimension of a 3D Gaussian "ball".
3 comentarios
Image Analyst
el 26 de Mayo de 2015
Of course, just use x - xCenter. The usual offset formula like for all mathematical formula like you're used to. But you're not creating a 3D matrix, you're creating a 2D one. Just look - 2 indexes. That means it's 2D. If it were 3D, you'd have to have 3 indexes, one for x, one for y, and one for z.
Más respuestas (0)
Ver también
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!