Write a function that checks whether an element occurs in a list.

function Checking(x)

a=([1,3,5,8,9]);

if x==a
    disp('It is an element')
else 
    disp('Not an element')
end
end

Answer 1

[Stephen23]

Actually your code just needs the addition of any to work correctly:

function Checking(x)
a = [1,3,5,8,9];
if any(x==a)
    disp('It is an element')
else 
    disp('Not an element')
end
end

and here it is being tested:

>> Checking(2)
Not an element
>> Checking(3)
It is an element

Read the if documentation carefully to know why this works!

Answer 2

[Walter Roberson]

function Checking(x)
   if ismember(x, [1,3,5,8,9])
       disp('It is an element')
   else
       disp('Not an element')
   end
end

Answer 3

[Sreeja Banerjee]

Hi Yeap,

Assuming that x is the element you want to check and a is the array, this function will not because you are comparing a 1x1 double with a 1xn double array. You need to compare each element of a with that of x.

Please look at the following code where I have used a FOR loop:

function Checking(x)
a=([1,3,5,8,9]);
for i = 1:length(a)
if x==a(i)
    disp('It is an element')
else
disp('Not an element')
end
end

[Walter Roberson]

Note that will say it is Not an element once for each element of "a" that it does not equal.