generating a weibull channel on Matlab

Hi,

I am new here.. I just have a doubt on how to create a Weibull channel on Matlab. For Rayleigh, I know it can be given as: h = 1/sqrt(2)*[randn(nRx(jj),N) + j*randn(nRx(jj),N)] where, nRx is the length i assumed and N is the number of bits in this case.

But how can I generate Weibull channel in the same manner ?

Please help me in this regards. That will be much appreciated.

Thanks and regards,

Raj.

Answer 1

[bym]

hw = lamda.*(-log(rand(nRx(jj),N)).^(1/beta))

where lamda & beta are your Weibull parameters. BTW you can generate your Rayleigh channel by using beta = 2

[raj0689]

Thanks a lot.. :)

now i can proceed with my project with your help.. :)

[yogesh chinnaraja sundararajan]

can any one help me what values can be substituted for Weibull parameters lamda and beta in the above equation hw= lamda.*(-log(rand(nRx(jj),N)).^(1/beta))

[can]

What about Rician Channel? How can I generate Rician channel in the same manner ? Please help me, Thanks and regards.

[senem cönger]

lamba ve beta kaç alınmalı burada?