precise selection in a for loop
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Hello, I just created a for loop and this is correct, but now I would only select positions from 30 to 48 for each "essai" but I am not sur how to do that whithout matrix size problem...
for essai = 1:length (nb_essai)
% for essai = 1:length (nb_essai)
num_ess = [];
num_ess = find (num(:,24) == essai);
Val_CursX_ess = num(num_ess,6);
Val_CursY_ess = num(num_ess,7);
Val_Quest_ess = txt(num_ess,36);
Val_Indice_ess = txt(num_ess,40);
Val_Valid_ess = txt(num_ess,33);
Respuestas (1)
Walter Roberson
el 17 de Jul. de 2015
After
num_ess = find (num(:,24) == essai);
add
num_ess = num_ess(num_ess >= 30 & num_ess <= 48);
10 comentarios
Alexandre Williot
el 17 de Jul. de 2015
Editada: Alexandre Williot
el 17 de Jul. de 2015
Walter Roberson
el 18 de Jul. de 2015
I do not understand that code.
What is class(Question_interet) ? Is it character array or is it cell array of string?
Why are you using those strange find() on strcmp() instead of using the two-output version of ismember() ?
[found, idx] = ismember('string', Cell_Array_Of_Strings)
Alexandre Williot
el 18 de Jul. de 2015
Walter Roberson
el 18 de Jul. de 2015
Please rewrite your code using ismember()
Also please note that there is no need to test
strcmp() == 1
The result of strcmp() is true or false directly so you can leave out the "== 1" such as
if strcmp(A,B)
or
find(strcmp(A,B))
Alexandre Williot
el 19 de Jul. de 2015
Walter Roberson
el 19 de Jul. de 2015
Yes, it probably is.
Alexandre Williot
el 19 de Jul. de 2015
Walter Roberson
el 19 de Jul. de 2015
Okay, so comment out that change of mine, rewrite the resulting version using ismember() and so on, and then uncomment the line and test the resulting code.
Alexandre Williot
el 19 de Jul. de 2015
Alexandre Williot
el 19 de Jul. de 2015
La pregunta está cerrada.
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