How to find the day number of any year from a date?
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    Md. Golam Mostafa
 el 23 de Jul. de 2015
  
    
    
    
    
    Editada: Sergey Kostrukov
 el 12 de Feb. de 2022
            I am very new in programming and therefore it is probably a novice's question. I have to write a script that takes a number of day(dd), month(mm) and year(yyyy)values arranged in three separate columns of a MATLAB variable and gives the day number of the year(e.g. for 03 March 2012, 31+29+3=63) as output.
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  Peter Perkins
    
 el 23 de Jul. de 2015
        If you are using R2014b or later, the datetime data type allows you to compute the day of year using the day function:
>> x = [2012 1 2; 2012 3 3; 2013 3 3]
x =
        2012           1           2
        2012           3           3
        2013           3           3
>> d = datetime(x)
d = 
   02-Jan-2012
   03-Mar-2012
   03-Mar-2013
>> day(d,'dayofyear')
ans =
     2
    63
    62
2 comentarios
  Peter Perkins
    
 el 24 de Jul. de 2015
				Presumably, you are not "using R2014b or later". datetime did not exist prior to that.
Más respuestas (3)
  Andrei Bobrov
      
      
 el 24 de Jul. de 2015
        x = [2012 1 2; 2012 3 3; 2013 3 3];
d = datenum(x);
out = d - datenum(year(d),1,1) + 1;
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  Sergey Kostrukov
 el 12 de Feb. de 2022
        
      Editada: Sergey Kostrukov
 el 12 de Feb. de 2022
  
      Fractional value of days since biginning of the year (0-364.9999):
daysFrac = days(currentTime - datetime(year(currentTime), 1, 1, TimeZone=currentTime.TimeZone))
To get the whole number starting from 1 (i.e. day index):
floor(daysFrac + 1)
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