If loop using cell arrays
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el 14 de Sept. de 2015
Comentada: Titus Edelhofer
el 14 de Sept. de 2015
Hi,
I have 2 matrices:
A with 24 arrays of each different length (i.e. A{1} 2362x1, A{2} 2341x1) defining salaries
B with 24 arrays of each different length (i.e. A{1} 2362x1, A{2} 2341x1) contains either a 0 or a 1
And last I have 2 boundary values C= 2600 and D= 1700.
I want to check the following:
if B(each value) == 0 && A(each value) > C
A(this value)= C
elseif B(each value) == 1 && A(each value) > D
A(this value)= D
end
Can anyone help me out?
1 comentario
Walter Roberson
el 14 de Sept. de 2015
There is no such thing as an "if loop". There are "for loop" and there are "while loop" and there are "if statement". A loop would have to execute its body multiple times, but "if" executes the body only 1 time or 0 times.
Respuesta aceptada
Guillaume
el 14 de Sept. de 2015
You don't need any if. Just use logical operations. Your first condition is to replace elements when B is false (i.e. B==0 or simply ~B) and A greater than C, so is simply writen as A(~B & A>C). Similarly your second condition is simply A(B==1 & A>D) (which simplifies to A(B & A>D). You just have to apply that to each cell of the cell arrays:
for cellidx = 1:numel(A)
a = A{cellidx};
b = B{cellidx};
a(~b & a>C) = C;
a(b & a>D) = D;
A{celldix} = a;
end
Más respuestas (1)
Titus Edelhofer
el 14 de Sept. de 2015
Hi,
I'm not 100% sure I understand what you want to do, but I guess it should be like this
for i=1:length(A)
if all(B{i}(:)==0 & A{i}(:)>C)
A{i}(:) = C;
elseif all(B{i}(:)==1 & A{i}(:)>D)
A{i}(:) = D;
end
end
Titus
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