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Why this message error?

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fede
fede el 22 de Sept. de 2015
Comentada: Stephen23 el 23 de Sept. de 2015
n=size(prices,2);
M_coint=zeros(n,n);
for i=1:n;
j=1:n;
M_coint(i,j)=cadf(prices(:,i),prices(:,j),0,1);
M_coint(i,j)=M_coint.adf;
end
message error: The following error occurred converting from struct to double: Error using double Conversion to double from struct is not possible.
  1 comentario
fede
fede el 22 de Sept. de 2015
cadf give the following results: ans =
alpha: -0.0199
adf: -3.0082
crit: [6x1 double]
nlag: 1
nvar: 1
meth: 'cadf'
I want to pull out the result of adf

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Stephen23
Stephen23 el 22 de Sept. de 2015
Editada: Stephen23 el 22 de Sept. de 2015
cadf does not seem to be an inbuilt MATLAB function, and you give no information about how it is defined or the output that it returns. And you also don't give us the complete error message (which tell us the line), so we have to also guess where this error is occurring in your code.
I like guessing games, so lets try.
First you define
M_coint=zeros(n,n);
which means M_coint is a matrix of class double. Then if we assume that cadf returns a structure, then the line
M_coint(i,j)=cadf(...)
will try to allocate that structure to M_coint.
Ouch! Allocating a structure to a double is an error! It does not work.
  4 comentarios
fede
fede el 22 de Sept. de 2015
mmmm ok the error message disappear, but I have not that I want. I have a matrix, in which in the each columns I have the single stocks, and in the row the time serie price. For example
IBM JPM C p11 p12 p13 p21 p22 p23 .................... pn1 pn2 pn3
I want obtain a output as a var-cov matrix, but in place of the covariance the score of cointegration test, as the following table.
ibm jpm c
ibm - -3.2 -4.2
jpm -1.2 - -2.1
c -2.3 -4.3 -
I can not generate a code suitable to my needs
Stephen23
Stephen23 el 23 de Sept. de 2015
This is a different topic to your original question. Please search for solutions to this new topic in the documentation, on the internet, or in this forum.

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