buttLoop error message code lifted from Matlab example 60 Hz hum

plot of filtered data looks reasonable in fig(1)
srate = input ('Enter SAMPLE RATE for this subject(check log book!): ');
ChannelFirst = data.ECG;
Fs=srate;
t =( 0:length(data.ECG)-1)/fs;
plot(t,data.ECG);
ylabel 'Voltage (V)', xlabel 'Time (s)'
title 'Open-Loop Voltage with 60 Hz Noise'
d = designfilt('bandstopiir','FilterOrder',2, ...
'HalfPowerFrequency1',59,'HalfPowerFrequency2',61, ...
'DesignMethod','butter','SampleRate',Fs);
fvtool(d,'Fs',Fs) ;
buttLoop = filtfilt(d,openLoop); ERROR THIS LINE <===========================
figure (2);
plot(t,data.ECG,t,buttLoop);
ylabel 'Voltage (V)', xlabel 'Time (s)';
title 'Open-Loop Voltage', legend('Unfiltered','Filtered');
[popen,fopen] = periodogram(data.ECG,[],[],Fs);
[pbutt,fbutt] = periodogram(buttLoop,[],[],Fs);
plot(fopen,20*log10(abs(popen)),fbutt,20*log10(abs(pbutt)),'--')
ylabel 'Power/frequency (dB/Hz)', xlabel 'Frequency (Hz)'
title 'Power Spectrum', legend('Unfiltered','Filtered')
ERROR MESSAGE:
Error in HRcodetest (line 120)
buttLoop = filtfilt(d,openLoop);

 Respuesta aceptada

Looking at the documentation in the link, ‘openLoop’ is loaded in this line:
load openloop60hertz, openLoop = openLoopVoltage;
and is one of the variables in that .mat file. You have to substitute your own signal, apparently ‘ChannelFirst’, for ‘openLoop’.

2 comentarios

Thank you! As with my whole life with software, once you know the answer, it's obvious!
My pleasure!
I’ve reviewed that example before, so I recognised the problem once I realised you weren’t loading the example data.

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Preguntada:

Don
el 19 de Oct. de 2015

Comentada:

el 20 de Oct. de 2015

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