Reshape 2D matrix to 3D using time as 3rd dimension
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    iijoclu
 el 28 de Oct. de 2015
  
Hi,
I've got a A = n x n matrix and I want to convert this 2D matrix to a 3D one using time as the third dimension. So the 3D should show how the value of all the elements in the n x n matrix changes with respect to time.
I tried using the reshape function but to no avail.
Thanks!
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  Thorsten
      
      
 el 28 de Oct. de 2015
        If i is your related to your time and takes values 1,2,3, etc, and A is the n x n matrix at time point i, you can use:
B(:,:,i) = A;
2 comentarios
  Thorsten
      
      
 el 28 de Oct. de 2015
				
      Editada: Thorsten
      
      
 el 28 de Oct. de 2015
  
			You cannot use the values of kgrid.t_array, but instead 1:numel(kgrid.t_array). Your code should look something like below, assuming that you have a function that computes your NxN matrix for every timestep:
 for i=1:numel(kgrid.t_array)
   t = kgrid.t_array(i); % get the ith time value
   A = computeNxNmatrix(t, more parameters); %
   B(:,:,i) = A;
end
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  Matt J
      
      
 el 28 de Oct. de 2015
        I tried using the reshape function but to no avail.
Be more persistent. RESHAPE is the appropriate thing to use.
2 comentarios
  lmaree
 el 12 de Mzo. de 2021
				"Beyond the second dimension, the output, B, does not reflect trailing dimensions with a size of 1. For example, reshape(A,3,2,1,1) produces a 3-by-2 matrix." from the reshape documentation.
In my case, this is exactly what I need to multiply a spacial 2D matrix with a time vector. However, reshape doesn't have the functionality it seems...
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