Make this matrix multiplication more efficient

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Ignacio Echeveste
Ignacio Echeveste el 23 de Nov. de 2015
Comentada: Ignacio Echeveste el 26 de Nov. de 2015
I would like to do the following matrix multiplication much efficiently:
for i=1:n
Thanks in advance

Respuesta aceptada

James Tursa
James Tursa el 25 de Nov. de 2015
a = (B(1:n,:)*(A*b)).^2;
You dimensions for B look a little strange to me, since your calculations do not use all of the rows of B (hence the B(1:n,:) reduction above).
  1 comentario
Ignacio Echeveste
Ignacio Echeveste el 26 de Nov. de 2015
Yes, the dimensions were wrong. Thank you, it is much more efficient.

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Richa Gupta
Richa Gupta el 25 de Nov. de 2015
Hi Ignacio,
The code below reduces the time from 2.6 secs to 0.06 secs on my machine:
m = 1000; n = 500;
a = zeros(n,1);
b = rand(n,1);
A = rand(m,n);
B = rand(m,m);
for i=1:n
temp =(B(i,:)*A)*b;
a(i) = temp'*temp;
Hope this helps.


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