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How to calculate phase angle between two sine wave from vectors

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DEBASHIS PANDA
DEBASHIS PANDA el 3 de Dic. de 2015
Respondida: Taha el 31 de Dic. de 2015
Hi.. After solving my problem I am getting two sine waves. These two waves are variations of current and voltage. I want to determine the phase angle between them. Actually I have got graphs I have attached here.In
my case I want to determine it from vectors (numeric values).If I will FFT is it correct

Respuestas (3)

Taha
Taha el 31 de Dic. de 2015
% %
% %
close all;
clear all;
x = 0:1e-6:60e-3; % bis 60 ms mit 1µs Schritte
a = sin(2*pi*50*x);
b = sin(2*pi*50*x-pi);
y_rad=acos(dot(a,b)/(norm(a)*norm(b)))
y_deg=y_rad*360/(2*pi)
plot(x,a,x,b)
xlabel(['Winkel in degree ist: ',num2str(y_deg)],'Color','r')
grid on

David Young
David Young el 3 de Dic. de 2015
If you know the frequency, it is probably more accurate to fit a sine wave to each of the two vectors than to use the FFT. The problem with the FFT is that it fits harmonics of a wave whose period is equal to the length of the time series, and your signal may not lie at exactly one of those frequencies.
There are several contributions on the file exchange for fitting sine waves (search "harmonic fit"), and my own function is attached, or you could write your own.
Once you have fitted a sine wave to each data series, you just subtract the phase of one from the phase of the other.

Taha
Taha el 31 de Dic. de 2015
https://www.researchgate.net/post/How_can_one_find_the_angle_between_voltage_and_current_sinusoidal_waves_in_MATLAB_SIMULINK_environment
and here is the code: close all; clear all; x = 0:1e-6:60e-3; % bis 60 ms mit 1µs Schritte a = sin(2*pi*50*x); b = sin(2*pi*50*x-pi);
y_rad=acos(dot(a,b)/(norm(a)*norm(b))) y_deg=y_rad*360/(2*pi) plot(x,a,x,b) xlabel(['Winkel in degree ist: ',num2str(y_deg)],'Color','r') grid on

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