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If I have a set of values and I identify the probabiltiy density function, how do I get the smallest distance from a set of distances that correspond to those values?

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the_values = [200,215,250,350,400,450,550,650,750];
dist_1 = [10,20,30,40,50,60,70,80,90,100];
M = mean(the_values);
S = std(the_values);
PDF = normpdf(the_values, M, S);
plot(the_values, PDF);
I would like to effectively find the optimal minimum distance that is at the optimal maximum likelihood of the the_values (eg most probable, smallest distance). I was looking at the solver function fminsearch but I have no idea how I would generate a function to describe this situation as required by the fminsearch function parameter. So distance should cut the distribution plot in the best area.
  4 comentarios
Walter Roberson
Walter Roberson el 5 de Dic. de 2015
What trade-off are you willing to make between distance and probability? Given two candidates, if a distance is 10% larger but the probability is twice as high, should that be chosen? Given two candidates, if the distance was 5% larger and the probability was 1/2 % larger, should that be chosen?
We know that you are willing to make some trade-off because you are not just asking for the point with the largest probability density.
Or is the idea that your distribution has multiple areas of equal probability density, and that out of all of the sample points that have equally the highest probability density, you want the closest of those? If so then how much tolerance should be made for round-off error, since a minor difference in probability calculation could be caused by round-off error rather than actual difference in probability?
Ronan
Ronan el 6 de Dic. de 2015
So say the larger the distance you have the less likely. So the smallest distance should be the most probable in an ideal situation. eg the biggest expected peak of the distribution should be closer to the smallest distance. I don't mind how much trade off is needed.

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