What wrong with that counter ?

function [wr,count] = wr_blk(rst,clk,sig)
%#codegen
count = 0;

if (rst==0)
    wr=0;
else
    if((sig==1) && (clk==1))
        count = count + 1; 
    else
        count=0;
    end    
end
end

Thanks, Henry

[Torsten]

You don't set return parameter "wr" in case that rst is not zero.

And - as far as I can see - there is one "end" too much.

Best wishes

Torsten.

[Henry Buck]

OK, One end is for if condition and the other is for the function.

About wr signal - that correct, I need to set it to 1 ifthe counter will increment to 4 (for example). By seting if condition, the counter will increment ?

Thanks, Henry

[Torsten]

The counter will never increment to 4 since you reset it to zero each time you call the function. Thus the maximum value count can be is one.

Best wishes

Torsten.

[Henry Buck]

thanks,

So, how can I count the numbers of clk, while sig is high ?

[Henry Buck]

what is wrong with this one :

if (rst==0)

    count=0;
else
    if(sig==1)
        if(clk)
           count = count + 1; 
        end
    else
        count=0;
    end    
end

if (rst==0) wr=0; else if((count==4)) wr=1; else wr=0; end end

Thanks, Henry

[Torsten]

count = sum((sig==1) & (clk==1));

if sig and clk are arrays of the same size.

Best wishes

Torsten.

[Henry Buck]

Thank you Torsten but I need the counter to be increment as long as sig is high - the counter will count the numbers of clk(as long as sig is high, other will zero).

Can I do it in a way as I wrote it above ?

Thanks, Henry

[Torsten]

I guess that's what my suggested solution does.

My line of code outputs the number of ones in the array clk at the positions where sig = 1.

Best wishes

Torsten.

[Henry Buck]

Thanks