fitnlm w/ table using not all Variables

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Benedict Kriegler
Benedict Kriegler el 10 de Dic. de 2015
Comentada: Benedict Kriegler el 14 de Dic. de 2015
Hello,
I am looking for a way to specify a modelfun for a non linear regression, using fitnlm, without using all Variables of the table. mdl = fitnlm(tbl,modelfun,beta0) Is it somehow possible to specify a modelfun by using the VariableNames of the table including the response variable?
I already performed the regression with a new table, containing the relevant variables only, but i would like to filter the table by other variables and i would like to prevent from double storage of large datasets.
Thanks in advance,
Benedict

Respuesta aceptada

Tom Lane
Tom Lane el 13 de Dic. de 2015
You can specify modelfun using variable names:
load carsmall
t = table(MPG,Weight,Origin)
nlm = fitnlm(t,'MPG~b1+b2*Weight^b3',[1 1 1])
In this case the property nlm.Data will contain all the variables in the table, including Origin. However, you could pass in just the part of the table you need:
nlm = fitnlm(t(:,{'MPG' 'Weight'}),'MPG~b1+b2*Weight^b3',[1 1 1])

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