sum of function handle
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Dear all, i have the following function:
sum_{1<=i<j<=n}(X_i-X_j)
and i need to write it as function handle. Can anyone help me please. Best regards.
4 comentarios
Write it as a function first, then the function handle part is trivial.
Trying to go straight from what you have there to a function handle is probably an unnecessarily complicated step unless for some reason you aren't allowed to create actual functions.
Guillaume
el 15 de Dic. de 2015
Your function does not appear to be the same thing at all as the expression you wrote in your question. Why is there a third iterator k, why is there a square ^2 and later a square root sqrt ?
Respuestas (3)
Guillaume
el 15 de Dic. de 2015
"I need to write it as function handle". Why do you need it? As Adam says, work it out as a normal function.
Anyway:
sumdiff = @(x) sum(diff(x(nchoosek(1:numel(x), 2)), [], 2)); %assume x is a vector
The way this works:
- nchoosek returns all the possible combinations of i and j that satisfy 1<=i<j<=n
- these combinations are use to index the original array as two columns, x(i) in the first column, x(j) in the second
- diff calculates the difference between the 2nd and 1st column
- sum sum all the differences
4 comentarios
Heborvi
el 15 de Dic. de 2015
Guillaume
el 15 de Dic. de 2015
The matrix x may be unknown, that does not preclude writing the function as a regular function.
function s = sumdiff(x)
s = sum(reshape(triu(bsxfun(@minus, x(:), x(:).'), 1), [], 1)); %Matt's answer is more efficient than mine
end
You can include anything you like in a handle function if it isn't an anonymous function.
You literally just define your function and then use function handle syntax to create a handle to it. The function could be 5000 lines long if you really want (obviously not advisable!), e.g.
function s = sumdiff(x)
...
end
f = @(x) sumdiff(x)
s = f(x);
Matt J
el 15 de Dic. de 2015
f=@(X) sum( reshape( triu( bsxfun(@minus, X(:),X(:).'),1), [],1) )
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