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index out of bound

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sweta arya
sweta arya el 20 de En. de 2016
Cerrada: MATLAB Answer Bot el 20 de Ag. de 2021
intial_image=zeros(180,1);
for i=1:180
intial_image(i)=i;
end
y =zeros(30,1);
y = datasample(intial_image,30);
disp(y(2,1));
size3=0;
nBins=8;
Nind=0;
h1=0;
count=0;
for i=1:30
if(numel(y)==30)
jpgFileName = strcat('C:\Users\priya\Desktop\Fashion Photography\',num2str(y(i)), '.jpg');
I= imread(jpgFileName);
[row,col,m]=size(I);
size3=size3+ row*col;
count=count+1;
end
giving error:
can not access y(2,1) because numel(y)=1.
  2 comentarios
Stephen23
Stephen23 el 20 de En. de 2016
Please show us all of the error message. This means all of the red text.
Stephen23
Stephen23 el 20 de En. de 2016
The code needs to be simplified. Replace this:
initial_image=zeros(180,1);
for i=1:180
intial_image(i)=i;
end
with this:
initial_image = (1:180).';
There is no point in preallocating y like this:
y =zeros(30,1);
because it is completely reallocated on the very next line:
y = datasample(...)

Respuestas (1)

Walter Roberson
Walter Roberson el 20 de En. de 2016
Whatever
datasample(intial_image,30)
is, it is resulting in a scalar.
What is the result of
which -all datasample
? Is it from the Statistics Toolbox or does it resolve to one of your own routines?

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