how to use certain values to write a for loop?

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Siddharth Parmar
Siddharth Parmar el 22 de Feb. de 2016
Comentada: Siddharth Parmar el 25 de Feb. de 2016
X = [67;89;78;56;55;75;99];
f = [4;5];
for i = 1:length(X);
if i == f;
X1(i,1) = 5*X(i,1);
else
X1(i,1) = X(i,1);
end
end
I know that the way i have written the if expression is wrong but can someone tell how do I write the if expression such that it uses the values of f.. basically if i equals the value in the f matrix or array the first formula is used else the second.
Thanks for help.
Sid
  2 comentarios
Stephen23
Stephen23 el 25 de Feb. de 2016
Editada: Stephen23 el 25 de Feb. de 2016
There is absolutely no point in using a slow and ugly loop. Here is Walter Roberson's much better solution in full:
>> X = [67;89;78;56;55;75;99];
>> f = [4;5];
>> X1 = X;
>> X1(f) = 5 * X1(f)
X1 =
67
89
78
280
275
75
99
Siddharth Parmar
Siddharth Parmar el 25 de Feb. de 2016
I understand that it looks simple because I have modified my code and asked a simple question. Imagine if you have the array with 1000 rows in X and f. Then the loop simplifies it.

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Respuesta aceptada

Arnab Sen
Arnab Sen el 25 de Feb. de 2016
Hi Siddharth,
My understanding from your problem statement that you want to check whether the values of the variable 'i' is present in the vector 'f' in the if-statement. You can use in-built 'find' function for this purpose. 'find' function returns the indices of the vector which meet certain condition. If no match then it returns a empty vector. So you can write the if statement in the following way:
>>if(~isempty(f==i))
So, the whole script as below:
if true
% code
end
X = [67;89;78;56;55;75;99];
f = [4;5];
for i = 1:length(X);
%if i == f
if(~isempty(find(f==i)))
X1(i,1) = 5*X(i,1);
else
X1(i,1) = 1*X(i,1);
end
end
For more detail about 'find', refer to the following link:
  2 comentarios
Jos (10584)
Jos (10584) el 25 de Feb. de 2016
Use the single command any(..) rather than the three commands ~empty(find(..))
any(f==i)
Siddharth Parmar
Siddharth Parmar el 25 de Feb. de 2016
Thanks guys this is exactly what I was looking for.

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Más respuestas (1)

Walter Roberson
Walter Roberson el 25 de Feb. de 2016
Editada: Stephen23 el 25 de Feb. de 2016
ismember(i, f)
Or, you can use
X1 = X;
X1(f) = 5 * X(f);
with no loop.

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