How can I fill the area between a function and the vertical axis x = 0, either for positive or negative values of it?
3 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
OSCAR ZAMORA PICAZO
el 17 de Mzo. de 2016
Respondida: Mike Garrity
el 17 de Mzo. de 2016
I have several diagrams which plot one function. I want to fill an area between that function (lineal, curve..)and a the vertical axis x = 0. So, how can I fill the area, either for positive or negative values of it?
The function is a piecewise function. The code of one case is:
y_B1 = 0:0.01:h_poste; Mz_B1 = -((y_B1<=h_hc).*(R_Mz_v1_B+R_Vx_B1.*y_B1+((1/2).*y_B1.*y_B1*(Qwstr1/h_poste)*(1/3).*y_B1))+((y_B1>h_hc)&(y_B1<=h_CdPa)).*(R_Mz_v1_B+R_Vx_B1.*y_B1+((1/2).*y_B1.*y_B1*(Qwstr1/h_poste)*(1/3).*y_B1)+M_hc+(Esf_rad_hc+Qwc(1)).*(y_B1-(h_hc+ht)))+((y_B1>h_CdPa)&(y_B1<=cdg_mensula_y)).*(R_Mz_v1_B+R_Vx_B1.*y_B1+((1/2).*y_B1.*y_B1*(Qwstr1/h_poste)*(1/3).*y_B1)+M_hc+(Esf_rad_hc+Qwc(1)).*(y_B1-(h_hc+ht))+M_CdPa+(Esf_rad_CdPa_B+Qwc(3)).*(y_B1-(h_CdPa)))+((y_B1>cdg_mensula_y)&(y_B1<=h_sust)).*(R_Mz_v1_B+R_Vx_B1.*y_B1+((1/2).*y_B1*(Qwstr1/h_poste)*(1/3).*y_B1)+M_hc+(Esf_rad_hc+Qwc(1)).*(y_B1-(h_hc+ht))+M_CdPa+(Esf_rad_CdPa_B+Qwc(3)).*(y_B1-(h_CdPa))+M_mensula)+((y_B1>h_sust)&(y_B1<=h_Feed)).*(R_Mz_v1_B+R_Vx_B1.*y_B1+((1/2).*y_B1.*y_B1*(Qwstr1/h_poste)*(1/3).*y_B1)+M_hc+(Esf_rad_hc+Qwc(1)).*(y_B1-(h_hc+ht))+M_CdPa+(Esf_rad_CdPa_B+Qwc(3)).*(y_B1-(h_CdPa))+M_mensula+M_sust+(Esf_rad_sust+Qwc(2)).*(y_B1-(h_sust+ht)))+((y_B1>h_Feed)&(y_B1<=h_poste)).*(R_Mz_v1_B+R_Vx_B1.*y_B1+((1/2).*y_B1.*y_B1*(Qwstr1/h_poste)*(1/3).*y_B1)+M_hc+(Esf_rad_hc+Qwc(1)).*(y_B1-(h_hc+ht))+M_CdPa+(Esf_rad_CdPa_B+Qwc(3)).*(y_B1-(h_CdPa))+M_mensula+M_sust+(Esf_rad_sust+Qwc(2)).*(y_B1-(h_sust+ht))+M_Feed+(Esf_rad_Feed_B+Qwc(4)).*(y_B1-(h_Feed)))); figure ley_Mz_B1 = plot(Mz_B1,y_B1);grid; title('CASO DE CARGA B (Viento 1).Ley de esfuerzos flectores') xlabel('Momento flector Mz (N·m)'); ylabel('Altura (m)');
where Mz_B1 is the function represented and y_B1 is the vector of independent values.
NOTE: the black area has been made using Paint.
0 comentarios
Respuesta aceptada
Mike Garrity
el 17 de Mzo. de 2016
This post I did on the MATLAB Graphics blog might give you some ideas on how to do this.
0 comentarios
Más respuestas (0)
Ver también
Categorías
Más información sobre Polygons en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!