Finding a variable in a equation

Please, I'm new to MATLAB and I want to know how to solve a problem.
I have two variables with 2000 values (I choose 10 to put here):
x = [ 0 0.25 0.5 0.75 1 1.25 1.5 1.75 2 ];
y = [-3.6621 7.32421 -1.831054 -1.831054 -7.32421 3.6621 -1.83105 0.00023 0.00847]
These variables are in the equation: y = K((e^(x/25)) − 1)
I have to use Ordinary least squares (linear regression) or Semilogarithmic plot to find the "K" with the informations above of x and y.
If I choose linear regression I can use these functions: fit, fittype,fitoptions.
Thanks!

Respuestas (2)

Michael Bouser
Michael Bouser el 23 de Mzo. de 2016
Editada: Michael Bouser el 23 de Mzo. de 2016

0 votos

First, apply a little algebra. Rewrite your equation in the form "K=". You are going to need to isolate your variable.
Next, because you are using vector inputs, make sure you use ".*" or "./" to force Matlab to do the math "element by element" if you expect an answer in the form of a vector. I think you need to use exp() to do the "e^" part.
It looks like you are doing ok with using parentheses to "maintain order".

1 comentario

Befs .07
Befs .07 el 25 de Mzo. de 2016
Editada: Befs .07 el 25 de Mzo. de 2016
Actually, I have 2000 values of x and y (I choose 5 to put there) and I have to use Ordinary least squares Method. I can use these functions: fit, fittype,fitoptions.
Thanks for all!

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Roger Stafford
Roger Stafford el 25 de Mzo. de 2016
The following obtains a least squares value for K:
K = y/(exp(x/25)-1);
I am assuming x and y are still row vectors here and of the same length.

2 comentarios

Star Strider
Star Strider el 25 de Mzo. de 2016
‘Befs .07’ is constrained to using fit, fittype, and fitoptions.
Well, if ordinary least squares are called for, do this:
t = exp(x/25)-1;
K = sum(y.*t)/sum(t.^2);

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