How to make three successive "for" loops and start the next loop from the end of the previous one?

Hello everybody; hope you all are doing well :)

look i have a code that suppose to make 3 successive loops but i can't make actually 3 things:

1- only one for loop contain the 3 loops together instead of separating each alone..

2- i state a condition for the first loop to stop and so the second loop suppose to start but i want to now at what iteration it will stop ,, ex: i stated a condition to stop this loop and start the new one when the value of y(i+1)<=0 but i want to know when? at Y(150) or what? because i want the loops to be successive and start from the end point of the first..

hope my question is clear... here is the code

if true
  % code
clc,clear, close all

% Variables

% P= ball force % (u,v) velocity of ball in (X,y)= distanve/time --> (dx/dt) % u=dx/dt , v=dy/dt

%force of the ball in the x and Y direction % Px=-mzu Px= m. du/dt % Py=-mzv Py-mg = m. dv/dt

% z= air resistance (proportional to the square of the speed and ball radius) % z = const*(u.^2+v.^2) % z=CR^2/m *(sqrt(u.^2 + v.^2))

% angle of kick: Cos(x)= u/sqrt(u.^2+v.^2)

% Variables % R= ball raduis % m= mass of ball % g= gravity % w= angle of the kick % h= Choose a value h for the size of every step % OH: Object hight --> OHx, OHy % D1: distance from the player to the object % D2: distance from the object to the goal

% Intial conditions (Constants) R= 0.11; %unit in meter m= 0.4; % unit in kg g= 9.8; D1= 5; % unit in meters D2= 2.5; % unit in meters

% variable values w(1)= 45; % unit in degree u(1)= 100*cosd(w); v(1)= 100*sind(w); x(1)=0; y(1)=0;

% using Euler method; %n= v(1);

% first step size h1=0.005; t1=1000; % unit in sec w1= 45; % unit in degree u1(1)= 100*cosd(w1); v1(1)= 100*sind(w1); x1(1)=0; y1(1)=0;

        for i=1:t1;

          % position of the ball
          y1(i+1)=y1(i)+(h1*v1(i));
          x1(i+1)=x1(i)+(h1*u1(i));

        if y1(i+1)>0

            z1(i)= ((50*R.^2)/m) *(sqrt(u1(i).^2 + v1(i).^2));
            v1(i+1)=v1(i)-(h1*(g+(z1(i))*v1(i)));
            u1(i+1)=u1(i)-(h1*z1(i)*(u1(i)));

         else

     % second step size 
           w2= 30; % unit in degree (suppose to be the reflected angle) 
           u2(1)= 0.7*100*cosd(w2); % sppose to be 70% of the force that hit the ground 
           v2(1)= 0.7*100*sind(w2);
           % the step i stopped at ? how to find?
           x2(31)=x1(30);
           y2(31)=y1(30);     

       % position of the ball

            x2(i+1)=x(i)+(h1*u2(i));
            y2(i+1)=y(i)+(h1*v2(i));

            z2(i)= ((50*R.^2)/m) *(sqrt(u2(i).^2 + v2(i).^2));

            v2(i+1)=v2(i)-(h2*(g+(z2(i))*v2(i)));
            u2(i+1)=u2(i)-(h2*z2(i)*(u2(i)));

            end
         end

    % third step size 
  h3=0.1; 
  t3=5; % unit in 30
  w3= 15; % unit in degree
  u3(1)= 100*cosd(w3);
  v3(1)= 100*sind(w3);
  x3(1)=x2(15);
  y3(1)=y2(15);

          for i=1:t3
           % if x(i)=t1 ;
            %    n=x(i);
            %end

          % position of the ball
            x3(i+1)=x3(i)+(h3*u3(i));
            y3(i+1)=y3(i)+(h3*v3(i));

            z3(i)= ((50*R.^2)/m) *(sqrt(u3(i).^2 + v3(i).^2));

            v3(i+1)=v3(i)-(h3*(g+(z3(i))*v3(i)));
            u3(i+1)=u3(i)-(h3*z3(i)*(u3(i)));
        end
  end

[Mariam Sheha]

why nobody answer?! , i need your help please...