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find result from multiple if and range value

2 visualizaciones (últimos 30 días)
badrul hisham
badrul hisham el 10 de Abr. de 2016
Editada: Andrei Bobrov el 10 de Abr. de 2016
hello, can someone help me? i have a set of range and i need the number produced from the the range. example: if i input a value of 0.17,it will find 0.17 is in which range (in this case it is in between 0.138 to 0.205) and then it will display the number of that range category which is 6.0
0.0 To 0.068 = 7.0
0.069 To 0.137 = 6.5
0.138 To 0.205 = 6.0
0.206 To 0.274 = 5.5
0.275 To 0.342 = 5.0 .
0.343 To 0.410 = 4.5
0.411 To 0.479 = 4.0
0.480 To 0.547 = 3.5
0.548 To 0.615 = 3.0
0.616 To 0.684 = 2.5
0.685 To 0.752 = 2.0
0.753 To 0.821 = 1.5
0.822 To 0.890 = 1.0

Respuesta aceptada

Azzi Abdelmalek
Azzi Abdelmalek el 10 de Abr. de 2016
Editada: Azzi Abdelmalek el 10 de Abr. de 2016
Edit2
r=[0.0 .068 7.0
0.069 0.137 6.5
0.138 0.205 6.0]
a=0.032
b=mat2cell(r(:,1:2),ones(size(r,1),1),2)
idx=cellfun(@(x) x(1)<=a & x(2)>=a,b)
sprintf('the range of a is %0.1f',r(idx,3))
  5 comentarios
Azzi Abdelmalek
Azzi Abdelmalek el 10 de Abr. de 2016
Look again at edited answer. I think this is the good one
badrul hisham
badrul hisham el 10 de Abr. de 2016
thank you so much for your help sir. this works perfectly now

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Más respuestas (1)

Andrei Bobrov
Andrei Bobrov el 10 de Abr. de 2016
Editada: Andrei Bobrov el 10 de Abr. de 2016
x =[ 0 7.0000
0.0690 6.5000
0.1380 6.0000
0.2060 5.5000
0.2750 5.0000
0.3430 4.5000
0.4110 4.0000
0.4800 3.5000
0.5480 3.0000
0.6160 2.5000
0.6850 2.0000
0.7530 1.5000
0.8220 1.0000];
t = 0.890;
a = rand(30,1)*t;
[~,~,bin] = histcounts(a,[x(:,1);t]);
out = x(bin,2);

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