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Syntax Issue in If Statement Using Handles

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Jay
Jay el 11 de Abr. de 2016
Comentada: Jay el 11 de Abr. de 2016
I am trying to write an if statement in a function, to determine if the handles values are of valid type, as per the stipulation in the texts written above said handles in the GUI.
For handle 'edit1' I have written:
if handles.edit1 == NaN
set(handles.edtit2, 'enable', 'off') && set(handles.listbox1, 'string', 'Date must be of stated syntax')
else set(handles.edit2, 'enable', 'on')
end
During runtime the code skips to else not flagging
if handles.edit1 == Nan
as true thus setting the 'handles.edit2' off and having the error showing in listbox1.
What is wrong with my if statement?

Respuesta aceptada

Stephen23
Stephen23 el 11 de Abr. de 2016
Editada: Stephen23 el 11 de Abr. de 2016
You cannot test for equality of NaN's, because as the documentation clearly states, NaN's are not equal to each other. Use isnan instead:
>> handles.edit1 = NaN;
>> handles.edit1 == NaN
ans =
0
>> isnan(handles.edit1)
ans =
1

Más respuestas (1)

Walter Roberson
Walter Roberson el 11 de Abr. de 2016
Use ishghandle() instead testing for NaN .
  1 comentario
Jay
Jay el 11 de Abr. de 2016
Thanks Walter,
I will see if that does what I need.

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