How to remove rows having repeating elements from a matrix?

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If I have a matrix A=[ 1 2 1 4; 1 2 3 4; 3 2 1 4; 3 3 2 1] then I want a matrix as B=[ 1 2 3 4; 3 2 1 4] so that both the 1st and 4th row will be deleted as they have repeated elements. pls help me to find out the code.

Respuesta aceptada

Roger Stafford
Roger Stafford el 25 de Abr. de 2016
Editada: Roger Stafford el 27 de Abr. de 2016
t = false(1,size(A,1));
for k = 1:size(A,1)
u = unique(A(k,:));
t(k) = size(u,2)==size(A,2);
end
B = A(t,:); % Rows with repeated elements deleted

Más respuestas (1)

Baltam
Baltam el 25 de Abr. de 2016
The below method is not elegant but it works.
A=[ 1 2 1 4; 1 2 3 4; 3 2 1 4; 3 3 2 1];
index = zeros(1,size(A,1));
for i = 1:size(A,1)
if numel(unique(A(i,:))) == numel(A(i,:))
index(i)=1;
end
end
index = logical(index);
B = A(index,:);
Kind regards,
Baltam
  2 comentarios
Susmita
Susmita el 27 de Abr. de 2016
This code is also running correctly..thanks@Baltam
David Wagener
David Wagener el 1 de Dic. de 2019
The second version shown here while not as elegant works better if you have a large matrix and are using parallel processing. I'm not an expert by any means but the second version did not overload my machine like the first one did.

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