All result is integer instead double
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Hello, Why all result after divide isn't double? Just zero or one :( Thanks
input = imread('cameraman.tif');
B = 2;
L = 256;
[m , n] = size(input);
output = zeros(m,n);
output = double(output);
min = min(input(:));
max = max(input(:));
for i = 1 : m
for j = 1 : n
Xmn = double(input(i,j));
output(i,j) = (Xmn - min )/(max - min);
end
end
1 comentario
John D'Errico
el 25 de Abr. de 2016
It is a REALLY, REALLY, REALLY bad idea to write lines like this:
min = min(input(:));
max = max(input(:));
Note that once you do that, the functions min and max will no longer work properly! So the second time you try to run that code, it will now fail.
Respuestas (1)
Walter Roberson
el 25 de Abr. de 2016
0 votos
The variables you name "min" and "max" are the same data type as your input. If your input is uint8 then min and max are uint8. When you do an operation involving double and uint8, the result is always uint8.
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