How do you store all return values from a while loop in a vector in matlab ?

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Harshita Jain
Harshita Jain el 26 de Abr. de 2016
Editada: jgg el 27 de Abr. de 2016
I have this for now, but unfortunately it only stores the latest value of choice_breakfast.
while breakfast_choicerep == 'Y' || breakfast_choicerep == 'y'
choice_breakfast = menu('What do you eat for breakfast?',breakfast_items);
vector_choice_breakfast = [choice_breakfast]
breakfast_choicerep = input('Did you eat anything else for brekfast? (Y/N): ', 's');
end

Respuestas (1)

jgg
jgg el 26 de Abr. de 2016

You can just store it as a vector:

 vector_choice_breakfast  = cell(1000,1);
 count = 1;
 while breakfast_choicerep == 'Y' | breakfast_choicerep == 'y'
    choice_breakfast = menu('What do you eat for breakfast?',breakfast_items);
    vector_choice_breakfast(count) = choice_breakfast;
    count = count + 1;
    breakfast_choicerep = input('Did you eat anything else for brekfast? (Y/N): ', 's');
end

The only issue is that you have to make sure you handle what happens when more than 1000 breakfast items are eaten, which could involve throwing an error and handling it (say by resizing the vector) or simply disallowing more output.

  4 comentarios
Harshita Jain
Harshita Jain el 27 de Abr. de 2016
The vector_choice_breakfast = cell(1000,1); is what's causing the error. so i just left it as an empty array to begin with: vector_choice_breakfast = []; But now, it's not adding the first value i calculate for choice_breakfast before i started the while loop.
jgg
jgg el 27 de Abr. de 2016
Editada: jgg el 27 de Abr. de 2016
Try changing the brackets in the assignment instead:
vector_choice_breakfast{count} = choice_breakfast;
I thought you were saving character arrays, not floats.

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