if i have matrix how to do this operation on it ??

and if i have this matrix A , a , b

   A = [ 1 3 
         1 1 
         2 2 
         2 0  ]

   a = [ 4          which mean how there is one in A 
         2
         4
         2 ]

   b = [ 2          which mean how there is element in A 
         2 
         2 
         1 ]

after that i want to do this

F = zeros(4,5);
for k=1:n
 if m == ( a(k) + ( b(k) - 1 ))
   IF the condition is true then goes to the same k row in A and put it in F the ones like that

After apply this loop then in first row and in third row the condition is true

   F = [ 1 0 1 1 1 
         0 0 0 0 0
         1 1 0 1 1
         0 0 0 0 0 ]

[dpb]

What are m and n? You can, of course, write

a=sum(A,2);
b=sum(A~-0,2);

and undoubtedly can build whatever F logic is that builds it which certainly isn't clear to me from the description above.

[Firas Al-Kharabsheh]

n in number of rows and m is number of columns in F

[Firas Al-Kharabsheh]

in the loop for example m=5 , first row

 if 5 == ( 4 + ( 2-1) )  >>>> true then 

 look at matrix A in first row {1,3} which mean there is two 
 group of ones the first group is 1 and the second is three ones and there 
is a one zero between the groups this mean is 

 F(1) = [ 1 0 1 1 1 ]

Answer 1

[dpb]

>> m=5; n=length(A);     % define sizes
>> F=zeros(n,m);         % preallocate output
>> ix=find(sum(A,2)+sum(A~=0,2)-1==m);  % rows contain some ones
>> F(ix,:)=1;                           % start with all '1'
>> F(sub2ind(size(F),ix,A(ix,1)+1))=0   % zero the locations not '1'
F =
   1     0     1     1     1
   0     0     0     0     0
   1     1     0     1     1
   0     0     0     0     0
>>