Error :First input argument must be a function handle

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raghu k
raghu k el 2 de Mayo de 2016
Editada: Walter Roberson el 2 de Mayo de 2016
I am getting "First input argument must be a function handle."
%%Qsh=00;
L=100; W=100; %%Tox = 38.2*10^-9;
Er=16;
u=7000;%% cm2/v.s
e=04;%%%%%%%5Find out!!!!!!!!
Nf=10;%% cm2
R = 280;%% R = Rs/Rd;
hw = 56*10^-3*e;%% NOT SURE !!!!!!!!!!!!
Delta = 66.8*10^-3*e;%% NOT SURE !!!!!!!!!!!!
Pi = 3.14159265;
h=0;%%%%%%%5Find out!!!!!!!!
vf=02;0;%%%%%%%5Find out!!!!!!!!
B = 4;%%% Find OUt!!!!!!!!!!!
Ctop=05;%%%%%%%5Find out!!!!!!!!
w=01;%%5 Find Out !!!!!!!
%%For Loop
Vgsi = 5;
Vdsi=2;
V=Vdsi/2;
b=2;
%% Equation 3
s = sign(Ctop*(Vgsi-V) +e*Nf)
%% Equation 2
Vch = (s-Ctop+sqrt(Ctop^2+4*B*abs(Ctop*(Vgsi-V))+e*Nf))/(2*B)
%% Equation 1
Qsh = e*((-B/e)*abs(Vch)*Vch+Nf)
%% Equation 4
Qnetav = b*s*((-Ctop^2+sqrt(Ctop^2+4*B*abs(Ctop*(Vgsi-Vdsi/2)+e*Nf))/(2*B))^2)
%% Equation 5 for Npuddle
Npuddle = Delta^2/(pi*h^2*vf^2);
%% Equation 5 for Vsat
Vsatav = L+abs(Vdsi)*u*(pi*((abs(Qnetav)/e)+Npuddle))^0.5/w;
%% Equation 5
Id = u*W*integral(abs(Qnetav)+e*Npuddle,0,Vdsi)/(L+u*abs(integral((1/Vsatav),0,Vdsi)));
% Plot(Vgsi,Id)
Please help.
Thanks

Respuestas (1)

Walter Roberson
Walter Roberson el 2 de Mayo de 2016
Editada: Walter Roberson el 2 de Mayo de 2016
Id = u*W*integral(@(Qnetav) abs(Qnetav)+e*Npuddle,0,Vdsi) / (L+u*abs(integral(@(Vsatav) (1/Vsatav),0,Vdsi)));
Assuming, that is, that you want to integrate over Qnetav and Vsatav and that e and Npuddle are already defined.
However, remember integral(1/x,x=a..b) is ln(b)-ln(a) and when a = 0 the result is infinite, so your second integral is infinite if you are integrating over Vsatav . If you are integrating over some other variable then you would be integrating a constant and the result would be Vdsi/Vsatav with no need to integrate. Either way, there is no point in doing the second integral -- it is either infinite or a constant.

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