Borrar filtros
Borrar filtros

how to Design PID controller for second order untable process

3 visualizaciones (últimos 30 días)
How a PID controller can be designed for a second order SISO process, of the form -a/S^2-b, where a,b>0 .

Respuesta aceptada

Arkadiy Turevskiy
Arkadiy Turevskiy el 13 de Feb. de 2012
Not sure if that is what you are looking for, but here is how you could do it in Control System Toolbox:
>>a=1; % change to desired value
>>b=4; % change to desired value
>>s=tf('s');
>>plant=-a/(s^2-b);
>>C=pidtune(plant,'PID'); design pid controller
>>step(feedback(C*plant,1)); plot the step response of the closed-loop system
>>pidtool(plant); % open the GUI for interactive tuning
HTH. Arkadiy
  2 comentarios
Harshit Gole
Harshit Gole el 19 de Feb. de 2012
sir ,
after entering the command
"C=pidtune(plant,'PID');"
it is showing an error
"??? Undefined function or method 'pidtune' for input arguments of type 'tf'."
please guide me.
Walter Roberson
Walter Roberson el 19 de Feb. de 2012
pidtune is new as of R2010b
http://www.mathworks.com/help/toolbox/control/rn/bsllzup-1.html

Iniciar sesión para comentar.

Más respuestas (0)

Etiquetas

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by