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Solving 2 parameters equation

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Hamid
Hamid el 17 de Jun. de 2016
Comentada: Hamid el 17 de Jun. de 2016
Hi everyone,
my unknown parameters are D and nR, I want Rg will be less than 0.5
How is it possible?
p=100;
pi=3.14;
asec=0.2179;
k1=1.3663;
Lg=35;
Wg=32;
k2=5.6641;
Lr=3;
b=0.01;
R1=((p/(pi*Lc))*(log((2*Lc)/asec)+((k1*Lc)/sqrt(Lg*Wg))-k2));
R2=((p/(2*pi*nR*Lr))*(log((4*Lr)/b)-1+((2*k1*Lr)/(sqrt(Lg*Wg)))*(((sqrt(nR)- 1))^2)));
Rm= ((p/(pi*Lc))*(log((2*Lc)/Lr)+((k1*Lc)/sqrt(Lg*Wg))-k2+1));
Rg=((R1*R2)-(Rm^2))/((R1+R2)-(2*Rm));
Thank you.

Respuestas (1)

Roger Stafford
Roger Stafford el 17 de Jun. de 2016
I see no unknown variable ‘D’ here. Also the variable ‘Lc’ is not defined. Do you mean that Lc and nR are actually the two unknowns? Also you need to specifically define ‘Rg’.
This looks as though it calls for ‘fsolve’:
http://www.mathworks.com/help/optim/ug/fsolve.html
  1 comentario
Hamid
Hamid el 17 de Jun. de 2016
My bad,sorry
Na=(Lg/D)+1;
Nb=(Wg/D)+1;
Lc=(Lg*Nb)+(Wg*Na);
my unknown parameters are D and nR, I want Rg will be less than 0.5.
please write the right code for solving the equation, unfortunately I don't have enough time.
Thanks.

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