finding a string in a cell array

ids1='519448(EPS1MN)' '519448(EPS2MN)' '519448(EPS3MN)' '519448(EPS4MN)' '519448(EPS5MN)' '519448(LTMD)' '519448(P)' '519448(DPS)' '519448(EPS)'

I want to find the cell that has embedded in it EPS1MN ,....EPS5MN

writing the following codes:

x2a=find(~isempty(strfind(ids1,'EPS1MN'))); % select rows.
    x2b=find(~isempty(strfind(ids1,'EPS2MN'))); 
    x2c=find(~isempty(strfind(ids1,'EPS3MN'))); 
    x2d=find(~isempty(strfind(ids1,'EPS4MN'))); 
    x2e=find(~isempty(strfind(ids1,'EPS5MN')));

is returning a value of 1 for x2a...x2e which is obviously wrong since the answers should be 1,2,...5

I am wondering what went wrong?

[Azzi Abdelmalek]

wesso commented

the two answers work well with EPS1...EPS5 but they fail to identify the cell when the cell is (P). (i.e I want the answer to identify cell '519448(P)' and gets an answer of 7. Any help with this?

[Azzi Abdelmalek]

If we give you the solution with (P), you will ask again it's not working with (T) or another string!

Answer 1

[Azzi Abdelmalek]

ids1={'519448(EPS1MN)'
'519448(EPS2MN)'
'519448(EPS3MN)'
'519448(EPS4MN)'
'519448(EPS5MN)'
'519448(LTMD)'
'519448(P)'
'519448(DPS)'
'519448(EPS)'}
out=find(~cellfun(@isempty,regexp(ids1,'EPS[12345]MN')))

Answer 2

[Thorsten]

out = find(cell2mat(regexp(ids1, 'EPS[1-5]MN')))