Efficient moving average of scattered data
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Chad Greene
el 28 de Jun. de 2016
Respondida: Chris Turnes
el 9 de Mzo. de 2017
I have some scattered data and I'd like to take something similar to a moving average, where I average all values with in some radius of each point. I can do this with a loop, but I'd like a more efficient approach. Any ideas?
Here's a working example I'd like to make more efficient:
x = randi(100,45,1) + 20+3*randn(45,1) ;
y = 15*sind(x) + randn(size(x)) + 3;
figure
plot(x,y,'bo')
radius = 10;
ymean = NaN(size(x));
for k = 1:length(x)
% Indicies of all points within specified radius:
ind = abs(x-x(k))<radius;
% Mean of y values within radius:
ymean(k) = mean(y(ind));
end
hold on
plot(x,ymean,'ks')
legend('scattered data','radial average','location','southeast')
1 comentario
Walter Roberson
el 28 de Jun. de 2016
When I read the title I thought you might mean "sparse", and was thinking about how I might do an efficient moving average on sparse data.
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Chris Turnes
el 9 de Mzo. de 2017
If you can upgrade to R2017a, this functionality can now be achieved through the 'SamplePoints' name-value pair in the moving statistics. For your example, you would do something like movmean(y, 2*radius, 'SamplePoints', x); (though you'd need to sort your x values first).
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Walter Roberson
el 28 de Jun. de 2016
pdist() to get all of the distances simultaneously. Compare to the radius. Store the resulting mask. Multiply the mask by repmat() of the y value, and sum along a dimension. sum the mask along the same dimension and divide the value sum by that count. Result should be the moving average.
3 comentarios
Walter Roberson
el 30 de Jun. de 2016
Editada: Walter Roberson
el 30 de Jun. de 2016
I wonder if looping pdist2() would be efficient? Eh, it probably just adds unnecessary overhead to a simple Euclidean calculation.
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