Replacing NaN with its succeeding values

I have an array which should replace the NaN with its succeeding value. For example:

A=[NaN NaN 1 1 0 0 NaN 0 NaN 1 1] 
then output should be
B=[1 1 1 1 0 0 0 0 1 1 1].

Can someone please help me with this?

Answer 1

[Brendan Hamm]

This is simply a 1-dimensional interpolation using the next method with extrapolation:

A=[NaN NaN 1 1 0 0 NaN 0 NaN 1 1]   
x = 1:length(A); % Create a vector of indices
idx = ~isnan(A); % Find the locations of valid data
% Use the good data to interpolate on all the locations in x.
B = interp1(x(idx),A(idx),x,'next','extrap')

[Andrei Bobrov]

+1

Answer 2

[Andrei Bobrov]

A=[NaN NaN 1 1 0 0 NaN 0 NaN 1 1];

z = flip(A(:));
x = ~isnan(z);
z = z(x);
B = flip(z(cumsum(x)))';