Array using for loop: using sprintf
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Ullas Rajvanshi
el 12 de Sept. de 2016
Comentada: Stephen23
el 12 de Sept. de 2016
Make the following two vectors, each with the same number of elements (77). v1: a 1D-array with random numbers (floats) between 0 and 8515.0 . v2: the nearest integer value corresponding to every element of v1. now use the sprintf() command to print a table with 77 rows and 3 columns. The first column contains v2 (displayed as integers, so 41 instead of 41.000). The second column contains v1, displayed as floats with 2 decimals. The third column contains v1 displayed in scientific notation, with 3 decimals. I know we have to make use of for loop in this, but how?
Thanks in advance
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Stephen23
el 12 de Sept. de 2016
@Ullas Rajvanshi: what have you tried so far?
If we do you work for you, how do you expect to learn anything from that course?
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Stephen23
el 12 de Sept. de 2016
Editada: Stephen23
el 12 de Sept. de 2016
You could use a loop like this:
- define the two vectors, say X and Y.
- loop over them, using for k = 1:numel(X).
- use indexing each loop to access the vector elements
- call sprintf with those values.
But actually you don't need to use a loop at all. Have a look at this:
>> M = 9*rand(1,5);
>> fprintf('%4.0f,%7.2f,%12.3e\n',[M;M;M])
7, 6.82, 6.820e+00
7, 6.69, 6.688e+00
4, 3.53, 3.530e+00
6, 5.90, 5.899e+00
2, 1.54, 1.541e+00
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Stephen23
el 12 de Sept. de 2016
@Ullas Rajvanshi: I am glad that you got motivated. I really do wish you lots of luck and fun learning MATLAB! And please come and ask questions when something does not work for you.
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