morton scanning for image size of 256*256 .

i found out this as for 4*4 matrix from matlab central

 clc;
 clear all;
 close all ;
 n=2;
 ind=morton(n);
 a=reshape(1:4^n,2^n,2^n);
 disp(a)

here is the matlab function

 function ind=morton(n);
 % MORTON(N) return the morton permutation order for array of size 2^N
 % e.g.
 % n=2;
 % matrix size is 2^n
 % ind=morton(n);
 % d=fix(rand(2^n,2^n)*10);
 % disp(d)
 % disp(d(ind))
 linind4=(1:4^n)-1; %start index count for array at zero
 ind4str=dec2base(linind4,4); %convert indices to base-4
 b1=dec2bin(str2num(ind4str(:,1))); %split each base-4 into two base-2numbers
 b2=dec2bin(str2num(ind4str(:,2)));
 rb=[b1(:,1) b2(:,1)]; %the rows are given by the first bits of b1 and
 b2
 cb=[b1(:,2) b2(:,2)]; %the columns are given by the second bits of b1 and b2
 r=bin2dec(rb)+1; %convert the row from bit to decimal
 c=bin2dec(cb)+1; %convert column
 ind=[2^n*(c-1)+r]'; %make a linear row index into array for easyaddressing
 %morton.m ends

----------------------------------------------------

i require to do this for whole image with out looping infinitely ..

can you please any one give the way by block processing

[vishnu]

i get infinite loop and can able to proceed it .. please any one help ?

[vishnu]

how can we create an morton order?

Answer 1

[Walter Roberson]

http://www.mathworks.com/matlabcentral/fileexchange/10496-listless-speck-lsk/content/mapping.m

[vishnu]

thank you sir .. i have already refered this code .. since i was not able to understand this how to use for the 256*256 image with morton scanning of follwing function

function A = mapping(n)

% To create a Morton Scan order matrix

if n == 2

A = [1 2; 3 4];

else

B = mapping(n/2);

A = [B B+(n/2)^2; B+(n/2)^2*2 B+(n/2)^2*3];

end

what is n and where the input image .. please reply

[vishnu]

where tha array is to have the scanned order of all the values of image .. i am unable to understand this .. please clarify with this

[vishnu]

pls kindly help me

[Walter Roberson]

A = mapping(256)

Then A has the index list for the scan order, and you would index your image at A.

[vishnu]

but i get error like this .. Maximum variable size allowed by the program is exceeded.

Error in ==> morton at 10

linind4=(1:4^n)-1; %start index count for array at zero

.. i am totally confused sir.. i take a image and those image values to be an array representation according to morton order .. its an assignment for me .. please help me .. i want to learn about this

[Walter Roberson]

For the purpose of your morton code, n should be 8.

But that doesn't have anything to do with the code I referred you to, which is the code you asked about in your comment here. Do not use both routines together: only use one of them.