FFT issue
1 visualización (últimos 30 días)
Mostrar comentarios más antiguos
When I attempt a Fourier Transform of my data, v, all the values of Y are NaN + NaNi
%v(t)
t=-1.5:0.001:1.5; %time, s
B=1.5*pi; %T
f0=20; %Hz
for i=1:length(t);
v(i)=(B*sin(2*pi*f0*t(i)))/(pi*t(i));
end
plot(t,v);
max(v) %Voltage,V
min(v) %Voltage,V
%Fourier Transform
Y=fft(v)
Any clues as to why this is occurring??
Thanks guys
0 comentarios
Respuesta aceptada
Walter Roberson
el 3 de Mzo. de 2012
Your time range includes time 0, and your v(i) for time 0 is 0/0 which is NaN. Once you have a NaN in your data, it is going to "pollute" everything else when you do the fft()
Más respuestas (2)
B T
el 3 de Mzo. de 2012
2 comentarios
Walter Roberson
el 4 de Mzo. de 2012
Do you possibly need to fftshift() to get what you are looking for?
Ver también
Categorías
Más información sobre Discrete Fourier and Cosine Transforms en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!