convert 16 bit image to 8 bit image

how to convert 16 bit image to 8 bit image

Answer 1

[Jan]

The uint16 image used values from 0 to 2^16-1, while the uint8 images use a range from, 0 to 2^8-1 only. If you just cast the original values to uint8, the saturation will destroy a lot of information. Better use:

img8 = uint8(img16 / 256);

[Wayne King]

good point Jan, I forgot to say that.

[dror yemini]

yes but you loase somthing better before take bits with information so maybe do equalization of histogram before conversion ?

Answer 2

[Rasmus Herlo]

OBS: Jan's answer will do absolutely fine, if your image is optimized to use the entire scale. However, if your pixel values are only occupying a fraction of the available bits (common in much imaging), the direct conversion will lead to a significant loss of information. In addition, you might want to get your image on 1:2^16 (instead of 0:2^16-1) before normalizing.

Image conversion in software like ImageJ therefore uses linear scaling, and one would typically apply a similar approach here, by:

Input: Im16 'uint16' (any 16bit image)

dbIm16 = double(Im16)+1
dbIm16 = min(dbIm16(:)); db16max = max(dbIm16(:));
TgBit = 8; % or any other lower bit scale

% example with 16bit to 8bit
Norm_wOffSet = dbIm16/db16max; % maintaining putative offset from 0 in the data
Im8_wOffSet = uint8(Norm_wOffSet*2^TgBit-1); % back to 0:2^8-1

Norm_woOffSet = (dbIm16-db16min)/(db16max-db16min); % Scales linearly to full range
Im8_woOffSet = uint8(Norm_woOffSet*2^TgBit-1); % back to 0:2^8-1

[Tiziana]

Thank so much for your answer. Could I ask you the reasons of this "you might want to get your image on 1:2^16 (instead of 0:2^16-1) before normalizing"? Thank you very much.

Answer 3

[Wayne King]

You can use uint8() to cast the image into unsigned 8-bit integers. Or int8() for signed 8-bit integers.

    X = uint8(ones(10,10,'uint16'));
    class(X)