Array that contains a geometric series

Hi, Is there a short way to create an array in which the elements are making a geometric series?
like for example the following array:
x=[1 2 4 8 16 32 64]
Thanks, Shir

 Respuesta aceptada

Roger Stafford
Roger Stafford el 19 de Dic. de 2016
A general form for a geometric series is:
[a,a*r,a*r^2,a*r^3,...]
You can generate n of these by:
s = a*r.^(0:n-1);

Más respuestas (1)

John D'Errico
John D'Errico el 19 de Dic. de 2016
2.^(0:6)

3 comentarios

shir shalom
shir shalom el 19 de Dic. de 2016
Thank you, but actually if I want to start at 0.5 then it won't work.
Is there a way using multiplication instead of ^ ?
You could have said that the first time. But what is wrong then with this?
2.^(-1:6)
It really won't work? I guess I need to learn this new math then.
Or, for a more general form, with some other start point:
0.1*2.^(0:6)
Could I have used a loop? Of course. But why? Learn to use Matlab.
shir shalom
shir shalom el 20 de Dic. de 2016
Yes, sorry of course it works. I guess I was too tired to think last night. Thanks alot!

Iniciar sesión para comentar.

Categorías

Más información sobre Programming en Centro de ayuda y File Exchange.

Etiquetas

Preguntada:

el 19 de Dic. de 2016

Comentada:

el 20 de Dic. de 2016

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by