Let's assume my vector is
A = [1 2 3 7 9 10 45 93 122 150]';
I want to put zeros in between these numbers.
A = [1 2 3 0 0 0 7 0 9 10 0 0 .....]';

 Respuesta aceptada

Andrei Bobrov
Andrei Bobrov el 20 de En. de 2017
Editada: Andrei Bobrov el 20 de En. de 2017

0 votos

One of ways:
A = [1 2 3 7 9 10 45 93 122 150]'
ii = randi(3,numel(A),1);
t = cumsum(ii) < numel(A);
ii = ii(t);
z = arrayfun(@(x)zeros(x,1),ii(1:end-1),'un',0);
C = mat2cell(A(1:sum(ii)),ii,1);
out = [C';[z',{[]}]];
out = cat(1,out{:});

3 comentarios

Deepti Ranjan Majhi
Deepti Ranjan Majhi el 20 de En. de 2017
Thank you for your reply. But, I want a vector of length 150X1.
Andrei Bobrov
Andrei Bobrov el 20 de En. de 2017
Please!
Deepti Ranjan Majhi
Deepti Ranjan Majhi el 20 de En. de 2017
Thank you for reply. I sort out the problem.

Iniciar sesión para comentar.

Más respuestas (1)

Jan
Jan el 20 de En. de 2017
Editada: Jan el 20 de En. de 2017

0 votos

A = [1 2 3 7 9 10 45 93 122 150]';
B = zeros(150, 1);
Index = [true(1, numel(A)), false(1, numel(B) - numel(A)];
Index = Index(randperm(numel(Index));
B(Index) = A;
Now the result is filled at random places by zeros such that the total length is 150.
[EDITED] Easier:
A = [1 2 3 7 9 10 45 93 122 150]';
B = zeros(150, 1);
Index = randperm(numel(B), numel(A));
B(Index) = A;

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el 20 de En. de 2017

Editada:

Jan
el 20 de En. de 2017

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