second order finite difference scheme

I am given data t=[0 1 2 3 4 5] and y(t)=[1 2.7 5.8 6.6 7.5 9.9] and have to evaluate the derivative of y at each given t value using the following finite difference schemes.
(y(t+h)y(th))/2h =y(t)+O(h^2)
(y(t+2h)+4y(t+h)3y(t))/2h =y(t)+O(h^2)
(y(t2h)4y(th)+3y(t))/2h =y(t)+O(h^2)
I started the code, but I haven't learned what to do in the second order case. This what I have so far for the first given equation:
t= 0: 1: 5;
y(t)= [1 2.7 5.8 6.6 7.5 9.9];
n=length(y);
dfdx=zeros(n,1);
dfdx(t)=(y(2)-y(1))/(t(2)-t(1));
for i=2:n-1
dfdx(1)=(y(i+1)-y(i-1))/(t(i+1)-t(i-1));
end
dfdx(n)=(y(n)-y(n-1))/(t(n)-t(n-1));
the error that returns is "Subscript indices must either be real positive integers or logicals." referencing my use of y(t). How do I fix this to make my code correct?

 Respuesta aceptada

Chad Greene
Chad Greene el 21 de Feb. de 2017
There's no need for the (t) when you define y(t). Same with dfdx. Also, make sure you change dfdx(1) in the loop to dfdx(i).
t= 0: 1: 5;
y= [1 2.7 5.8 6.6 7.5 9.9];
n=length(y);
dfdx=zeros(n,1);
dfdx=(y(2)-y(1))/(t(2)-t(1));
for i=2:n-1
dfdx(i)=(y(i+1)-y(i-1))/(t(i+1)-t(i-1));
end
dfdx(n)=(y(n)-y(n-1))/(t(n)-t(n-1));

6 comentarios

By the way, the gradient function gives the same results.
t= 0: 1: 5;
y= [1 2.7 5.8 6.6 7.5 9.9];
plot(t,gradient(y,t))
Margaret Winding
Margaret Winding el 22 de Feb. de 2017
Editada: Margaret Winding el 22 de Feb. de 2017
Thank you very much! I learned about the gradient function but my professor does not want us to use that for this problem.
I fixed the errors you mentioned, but it now gives me the same error "Subscript indices must either be real positive integers or logicals" but for dfdx=(y(2)-y(1))/(t(2)-t(1))
I don't understand what formatting error is occurring at this point, any ideas? Thank you so much!!
Torsten
Torsten el 22 de Feb. de 2017
dfdx(1)=(y(2)-y(1))/(t(2)-t(1))
Best wishes
Torsten.
Chad Greene
Chad Greene el 22 de Feb. de 2017
Ah, yes, sorry Margaret; thanks Torsten.
Margaret Winding
Margaret Winding el 23 de Feb. de 2017
Chad and Torsten,
Thank you so much for your help! I was able to get the correct answer :)
alburary daniel
alburary daniel el 3 de Ag. de 2018
and how will be the code for using a 4-point first derivative?

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