matlab indexing and swapping

 x = [6 5 3 5 9 10 438 4 1 4 7 0 4 8 4 2];
len = length(x);
minval = x(1);
for n = 1:len
    for i = 1:len
        if x(i) < minval
            minval = x(i);
        end
    end
    sortval(i) = minval;
    x(n find(x==minval)) = x(find(x==minval) n);
    x(n) = [];
end
disp(sortval)

I am trying to swap the position of n and my minval so I can delete that minval later and not affect the process of sorting later in the for loop.

Answer 1

[James Tursa]

This isn't going to work like you hoped. If you delete an element from the array with this line:

    x(n) = [];

Then there are no longer len elements in the x array, so this will eventually yield an error because i will be out of bounds for the shortened length of x (i.e., len is no longer the actual length of x):

    for i = 1:len
        if x(i) < minval

So first thing you need to do is rewrite your code to fix this problem, then we can worry about how to swap elements (if that step still remains in your fixed code).